Q:

To the nearest tenth, what is the distance between the points (1, –2, 5) and (0, 7, –4)?

Accepted Solution

A:
Answer:[tex]\boxed{12.8}\\[/tex]Step-by-step explanation:The coordinates of your points, (1, –2, 5) and (0, 7, –4), are 3D Β (x, y, z) coordinates. They represent the diagonal of a rectangular prism. The length of the sides are xβ‚‚ - x₁ = |0 – 1| Β  Β  = 1 yβ‚‚ - y₁ = |7 – (-2)| = 9 zβ‚‚ - z₁ = |-4 – 5| Β  = 9 The prism has the dimensions 9 Γ— 9 Γ— 1 as shown in the diagram. We can use the Pythagorean theorem to calculate the length of the diagonal, d Look first at the red diagonal on the base of the prism. xΒ² = 9Β² + 9Β² = 81 + 81 = 162 Now, look at the main diagonal. dΒ² = xΒ² + hΒ² = 162 + 1Β² = 162 + 1 = 163 d = √163 =12.8 [tex]\boxed{ \textbf{The distance between the two points is 12.8.}}\\[/tex]