To the nearest tenth, what is the distance between the points (1, β2, 5) and (0, 7, β4)?
Accepted Solution
A:
Answer:[tex]\boxed{12.8}\\[/tex]Step-by-step explanation:The coordinates of your points, (1, β2, 5) and (0, 7, β4), are 3D Β (x, y, z) coordinates. They represent the diagonal of a rectangular prism.
The length of the sides are
xβ - xβ = |0 β 1| Β Β = 1
yβ - yβ = |7 β (-2)| = 9
zβ - zβ = |-4 β 5| Β = 9
The prism has the dimensions 9 Γ 9 Γ 1 as shown in the diagram.
We can use the Pythagorean theorem to calculate the length of the diagonal, d
Look first at the red diagonal on the base of the prism.
xΒ² = 9Β² + 9Β² = 81 + 81 = 162
Now, look at the main diagonal.
dΒ² = xΒ² + hΒ² = 162 + 1Β² = 162 + 1 = 163
d = β163 =12.8
[tex]\boxed{ \textbf{The distance between the two points is 12.8.}}\\[/tex]